SOLUTION: please help me if any one can............... (if 10^x/10^y=100,then x.......options are (A)Y+2 (B)Y-2 (C)2-Y (D)2Y (E)Y/2 please explain me too how you did it

Algebra ->  Equations -> SOLUTION: please help me if any one can............... (if 10^x/10^y=100,then x.......options are (A)Y+2 (B)Y-2 (C)2-Y (D)2Y (E)Y/2 please explain me too how you did it      Log On


   



Question 924093: please help me if any one can...............
(if 10^x/10^y=100,then x.......options are
(A)Y+2
(B)Y-2
(C)2-Y
(D)2Y
(E)Y/2
please explain me too how you did it

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
%28+x%5Em+%29%28+x%5En+%29+=+x%5E%28+m+%2B+n+%29
x%5Em%2Fx%5En=x%5E%28m-n%29 ***
%28a%5Ep%29%5Eq+=+a%5E%28p%2Aq%29
...
10^x/10^y=100
10^(x-y) = 10^2 ****
x-y = 2 (Same Base, exponents equal Rule)
x = y + 2
....
re TY
What allows us to say: x-y = 2 Follows the Rules of Exponents.
10^(x-y)=10*10 The idea of "cut 10 on both Sides"
Does NOT follow the Rules for Exponents. (Don't go there Please :)
......Some Other Rules of Exponents:
a%5E0+=+1
x%5Em%2Fx%5En=x%5E%28m-n%29
%28+x%5Em+%29%28+x%5En+%29+=+x%5E%28+m+%2B+n+%29
%28a%5Ep%29%5Eq+=+a%5E%28p%2Aq%29
%28xy%29%5En+=+x%5En%2Ay%5En