SOLUTION: How do I solve 3y+3x=3 and 2y+6x=2 by substitution?

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Question 923179: How do I solve 3y+3x=3 and 2y+6x=2 by substitution?
Found 2 solutions by Rongtian, MathTherapy:
Answer by Rongtian(7) About Me  (Show Source):
You can put this solution on YOUR website!
-2(3y+3x)=(3)-2 ... -6y-6x=-6

-6y-6x=-6
2y+6x=2
(+)____________
-4y=-4
y=1

2(1)+6x=2
x=0
x=0
y=1

Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!

How do I solve 3y+3x=3 and 2y+6x=2 by substitution?


3y + 3x = 3_____3(y + x) = 3(1)_____y + x = 1______y = 1 - x ------- eq (i)

2y + 6x = 2_____2(y + 3x) = 2(1)______y + 3x = 1 ------ eq (ii)

1 - x + 3x = 1 ------- Substituting 1 - x for y in eq (ii)

- x + 3x = 1 - 1

2x = 0

x = 0%2F2, or highlight_green%28x+=+0%29



y = 1 - 0 ------- Substituting 0 for x in eq (i)

highlight_green%28y+=+1%29