SOLUTION: PLEASE help me I am stuck with this problem please
If (x+5)(x+p)=x^2+2x+k,then
(A)P=3 AND K=5
(B)P=3 AND K=-15
(C)P=-3 AND K=15
(D)P=3 AND K=15
(E)P=-3 AND K=-15
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-> SOLUTION: PLEASE help me I am stuck with this problem please
If (x+5)(x+p)=x^2+2x+k,then
(A)P=3 AND K=5
(B)P=3 AND K=-15
(C)P=-3 AND K=15
(D)P=3 AND K=15
(E)P=-3 AND K=-15
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Question 922415: PLEASE help me I am stuck with this problem please
If (x+5)(x+p)=x^2+2x+k,then
(A)P=3 AND K=5
(B)P=3 AND K=-15
(C)P=-3 AND K=15
(D)P=3 AND K=15
(E)P=-3 AND K=-15 Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website! (x+5)(x+p)=x^2+2x+k
x^2 + 5x + px + 5p = x^2 + 2x + k
x^2 + (5+p)x + 5p = x^2 + 2x + k
5p = k
.......
(5+p) = 2
p = -3 and k = -15
