SOLUTION: I'm trying to solve this equation. g^3 - 4g = 3g^2 - 12 I have gotten about here and am stumped after this. g(g^2 - 3g - 4) = -12 I need to know how to factor and gro

Algebra ->  Equations -> SOLUTION: I'm trying to solve this equation. g^3 - 4g = 3g^2 - 12 I have gotten about here and am stumped after this. g(g^2 - 3g - 4) = -12 I need to know how to factor and gro      Log On


   

Question 913181: I'm trying to solve this equation.
g^3 - 4g = 3g^2 - 12
I have gotten about here and am stumped after this.
g(g^2 - 3g - 4) = -12
I need to know how to factor and group this to solve for 0
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
g%5E3+-+4g+=+3g%5E2+-+12+

g%5E3+-+4g+-+3g%5E2+%2B+12+=+0+

g%5E3+-+3g%5E2+-+4g+%2B+12+=+0+

%28g%5E3+-+3g%5E2%29%2B%28-4g+%2B+12%29+=+0+

g%5E2%28g+-+3%29-4%28g-3%29+=+0+

%28g%5E2-4%29%28g+-+3%29+=+0+

%28g-2%29%28g%2B2%29%28g+-+3%29+=+0+

g-2=0, g%2B2=0, or g+-+3+=+0+

g=2, g=-2, or g+=+3+

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The three solutions are g=2, g=-2, or g+=+3+


Let me know if you need more help or if you need me to explain a step in more detail.
Feel free to email me at jim_thompson5910@hotmail.com
or you can visit my website here: http://www.freewebs.com/jimthompson5910/home.html

Thanks,

Jim