SOLUTION: For what value of k are the graphs of 12y=-3x+8 and 6y=kx-5 perpendicular? Thanks for your help.

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Question 912856: For what value of k are the graphs of 12y=-3x+8 and 6y=kx-5 perpendicular? Thanks for your help.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Convert to slope intercept form.
Perpendicular slopes are negative reciprocals.
12y=-3x%2B8
y=-%281%2F4%29x%2B2%2F3
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.
6y=kx-5
y=%28k%2F6%29x-5%2F6
So then,
-%281%2F4%29%28k%2F6%29=-1
k%2F24=1
highlight%28k=24%29
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graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C-%281%2F4%29x%2B2%2F3%2C4x-5%2F6%29