SOLUTION: Passing through (-6,-2) and (5,-3). (Write the equation with a positive coefficient of x.)

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Question 907821: Passing through (-6,-2) and (5,-3). (Write the equation with a positive coefficient of x.)
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

Solved by pluggable solver: Find the equation of line going through points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-6, -2) and (x2, y2) = (5, -3).
Slope a is .
Intercept is found from equation a%2Ax%5B1%5D%2Bb+=+y%5B1%5D, or -0.0909090909090909%2A-6+%2Bb+=+-2.54545454545455. From that,
intercept b is b=y%5B1%5D-a%2Ax%5B1%5D, or b=-2--0.0909090909090909%2A-6+=+-2.54545454545455.

y=(-0.0909090909090909)x + (-2.54545454545455)

Your graph:





so, y=-0.09x+-2.55 as the equation with a positive coefficient of x will be

0.09x%2By=+-2.55