SOLUTION: How do you do the following: 1. x^2-2x-48=0 2. 4x+5y=61 2x +5y=43 3. x^2+5x-24=0 4. 4x +y=10 -3x+3y=0

Algebra ->  Equations -> SOLUTION: How do you do the following: 1. x^2-2x-48=0 2. 4x+5y=61 2x +5y=43 3. x^2+5x-24=0 4. 4x +y=10 -3x+3y=0      Log On


   

Question 897381: How do you do the following:
1. x^2-2x-48=0
2. 4x+5y=61
2x +5y=43
3. x^2+5x-24=0
4. 4x +y=10
-3x+3y=0
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2-2x-48=0
%28x-8%29%28x%2B6%29=0
x=8 and x=-6
.
.
.
Subtract,
4x%2B5y-2x-5y=61-43
2x=18
x=9
Then,
4%289%29%2B5y=61
36%2B5y=61
5y=25
y=5
.
.
.
x%5E2%2B5x-24=0
%28x%2B8%29%28x-3%29=0
x=-8 and x=3
.
.
.
Simplify eq. 2,
-x%2By=0
y=x
Substitute,
4x%2Bx=10
5x=10
x=2
y=2