SOLUTION: Find the solution sets. 4x^2

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Question 89199: Find the solution sets.
4x^2 - 25 = 0
Found 2 solutions by Nate, praseenakos@yahoo.com:
Answer by Nate(3500) (Show Source):
You can put this solution on YOUR website!
4x^2 - 25 = 0
4x^2 = 25
x^2 = 25/4
x = +- 5/2
x = 2.5 and -2.5

Answer by praseenakos@yahoo.com(507) (Show Source):
You can put this solution on YOUR website!
Question
Find the solution sets.
4x^2 - 25 = 0

Answer.

This can be written as .....

, which is of the form,

We know that can be written as,
= (a + b) ( a - b)

Similarly

==> (2x + 5)( 2x - 5 ) = 0

==> either (2x + 5) = 0 or ( 2x - 5 ) = 0

==> 2x + 5 = 0
Subtract 5 from both sides.....

==> 2x - 5 - 5 = 0 - 5

==> 2x = -5

Divide both sides by 2

==>

==>

Now suppose 2x-5 = 0

Add 5 on both sides....

2x - 5 + 5 = 0 + 5

==> 2x = 5

Divide both sides by 2

==>

==>

So the solution set is = { 2.5, -2.5 }

Hope you found the explanation useful.

Regards.
Praseena

SOLUTION: Find the solution sets. 4x^2 - 25 = 0