SOLUTION: The sum of four numbers is 56. First number is twice as second and third number is as half of the second and fourth number is 3 times the sum of 1st and 2nd number. Find the number

Algebra ->  Equations -> SOLUTION: The sum of four numbers is 56. First number is twice as second and third number is as half of the second and fourth number is 3 times the sum of 1st and 2nd number. Find the number      Log On


   

Question 889067: The sum of four numbers is 56. First number is twice as second and third number is as half of the second and fourth number is 3 times the sum of 1st and 2nd number. Find the numbers?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
A%2BB%2BC%2BD=56
A=2B
C=%281%2F2%29B
D=3%28A%2BB%29=3%282B%2BB%29=3%283B%29=9B
Substituting,
2B%2BB%2B%281%2F2%29B%2B9B=56
%2825%2F2%29B=56
highlight%28B=112%2F25%29
Then,
A=2%28112%2F25%29
highlight%28A=224%2F25%29
.
.
C=%281%2F2%29%28112%2F25%29
highlight%28C=56%2F25%29
.
.
.
D=3%28224%2F25%2B112%2F25%29
D=3%28336%2F25%29
highlight%28D=1008%2F25%29