SOLUTION: equations in quadratic form; solve the equation for x; x^6-28x^3+27=0

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Question 886359: equations in quadratic form;
solve the equation for x;
x^6-28x^3+27=0
Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
x^6-28x^3+27=0
factor polynomial
(x^3 -27)(x^3-1) = 0
we have two cases
x^3 -27 = 0
x = 3
and
x^3 -1 = 0
x = 1
our two solutions are x = 3 or 1