SOLUTION: Really not good at word problems can anyone help me? Suppose that the length of a certain rectangle is 2 meters less than four times its width. The perimeter of the rectangle is

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Question 881735: Really not good at word problems can anyone help me?
Suppose that the length of a certain rectangle is 2 meters less than four times its width. The perimeter of the rectangle is 56 meters. Find the length and width of the rectangle.
And, The perimeter of a triangle is 42 inches. The second side is 1 inch more than twice thr first side, and the third side is 1 inch less than three times the first side. Find the lengths of the three sides of the triangle.
Found 2 solutions by ewatrrr, lwsshak3:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

     .

L + w = 28m

(4w-2) + w = 28m

     5w = 30m

      w = 6m  and L = 22m  4%2A6-2

And

 x + (2x+1) + (3x-1) = 42in

      6x = 42in

       x = 7in

7in, 15in, 20in are the lengths of the three sides (add to 42in)

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Suppose that the length of a certain rectangle is 2 meters less than four times its width. The perimeter of the rectangle is 56 meters. Find the length and width of the rectangle.
***
let x=width of rectangle
4x-2=length of rectangle
2(length+width)=perimeter
2(4x-2+x)=56
5x-2=28
5x=30
x=6
4x-2=22
width of rectangle=6 m
length of rectangle=22 m
...
And, The perimeter of a triangle is 42 inches. The second side is 1 inch more than twice the first side, and the third side is 1 inch less than three times the first side. Find the lengths of the three sides of the triangle.
***
let x=length of 1st side
2x+1=length of 2nd side
3x-1=length of 3rd side
x+2x+1+3x-1=42
6x=42
x=7
2x+1=15
3x-1=20
length of 1st side=7
length of 2nd side=15
length of 3rd side=20