SOLUTION: the question says find the equation for the line that is parallel to the line with the equation of (y-5)=1/2(x+1) passing through the point (-4,-5)

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Question 878874: the question says find the equation for the line that is parallel to the line with the equation of (y-5)=1/2(x+1) passing through the point (-4,-5)
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
The slope will be unchanged for parallel and the "point" to include in the point-slope form equation will be (-4,-5).

y%2B4=%281%2F2%29%28x%2B5%29;
One should understand how point-slope form works.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
the question says find the equation for the line that is parallel to the line with the equation of (y-5)=1/2(x+1) passing through the point (-4,-5)


The equation: y+-+5+=+%281%2F2%29%28x+%2B+1%29 has a slope of 1%2F2

The equation being formed will have the same slope, 1%2F2 since the lines of both equations are parallel

Using the slope, 1%2F2, the point (- 4, - 5), and the point-slope formula: y+-+y%5B1%5D+=+m%28x+-+x%5B1%5D%29, we get:

y+-+-+5+=+%281%2F2%29%28x+-+-+4%29

y+%2B+5+=+%281%2F2%29%28x+%2B+4%29

y+%2B+5+=+%281%2F2%29x+%2B+2%29

y+=+%281%2F2%29x+%2B+2+-+5%29

highlight_green%28highlight_green%28y+=+%281%2F2%29x+-+3%29%29