SOLUTION: From the top of a building, a rock is thrown straight up with an initial velocity of 32 ft. per second. The equation s = -16t^2 + 32t + 48 gives the height (s) of the rock (t) seco
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-> SOLUTION: From the top of a building, a rock is thrown straight up with an initial velocity of 32 ft. per second. The equation s = -16t^2 + 32t + 48 gives the height (s) of the rock (t) seco
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Question 878388: From the top of a building, a rock is thrown straight up with an initial velocity of 32 ft. per second. The equation s = -16t^2 + 32t + 48 gives the height (s) of the rock (t) seconds after its thrown. Find the maximum height reached by the rock. Answer by solver91311(24713) (Show Source):
Since your function has a negative lead coefficient, the graph is a parabola that opens downward. Therefore the vertex of the parabola is at the maximum value of the function.
The value of the vertex of is given by and the value of the function at the vertex is the function evaluated at this value. In other words, the vertex is at the point
You need the value of that gives the independent variable value of the vertex for which is given by and then you need to evaluate your height function at that value of
John
My calculator said it, I believe it, that settles it
