SOLUTION: need help learning how to factor. current problem is {{{ 6x^2+25x+11}}}.

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Question 872885: need help learning how to factor. current problem is +6x%5E2%2B25x%2B11.
Found 2 solutions by Alan3354, richwmiller:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
need help learning how to factor. current problem is +6x%5E2%2B25x%2B11.
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Factoring is trial and error.
+6x%5E2%2B25x%2B11
Notice that everything is positive, that makes it easier.
And, the only pair of factors of 11 is 1 & 11.
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It'll be:
(px + 1)*(qx + 11) where p*q = 6
Try pairs until you find the right pair.
It's either 1*6 or 2*3

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
The method can be organized. It is not completely trial and error.
Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)


Looking at the expression 6x%5E2%2B25x%2B11, we can see that the first coefficient is 6, the second coefficient is 25, and the last term is 11.



Now multiply the first coefficient 6 by the last term 11 to get %286%29%2811%29=66.



Now the question is: what two whole numbers multiply to 66 (the previous product) and add to the second coefficient 25?



To find these two numbers, we need to list all of the factors of 66 (the previous product).



Factors of 66:

1,2,3,6,11,22,33,66

-1,-2,-3,-6,-11,-22,-33,-66



Note: list the negative of each factor. This will allow us to find all possible combinations.



These factors pair up and multiply to 66.

1*66 = 66
2*33 = 66
3*22 = 66
6*11 = 66
(-1)*(-66) = 66
(-2)*(-33) = 66
(-3)*(-22) = 66
(-6)*(-11) = 66


Now let's add up each pair of factors to see if one pair adds to the middle coefficient 25:



First NumberSecond NumberSum
1661+66=67
2332+33=35
3223+22=25
6116+11=17
-1-66-1+(-66)=-67
-2-33-2+(-33)=-35
-3-22-3+(-22)=-25
-6-11-6+(-11)=-17




From the table, we can see that the two numbers 3 and 22 add to 25 (the middle coefficient).



So the two numbers 3 and 22 both multiply to 66 and add to 25



Now replace the middle term 25x with 3x%2B22x. Remember, 3 and 22 add to 25. So this shows us that 3x%2B22x=25x.



6x%5E2%2Bhighlight%283x%2B22x%29%2B11 Replace the second term 25x with 3x%2B22x.



%286x%5E2%2B3x%29%2B%2822x%2B11%29 Group the terms into two pairs.



3x%282x%2B1%29%2B%2822x%2B11%29 Factor out the GCF 3x from the first group.



3x%282x%2B1%29%2B11%282x%2B1%29 Factor out 11 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.



%283x%2B11%29%282x%2B1%29 Combine like terms. Or factor out the common term 2x%2B1



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Answer:



So 6%2Ax%5E2%2B25%2Ax%2B11 factors to %283x%2B11%29%282x%2B1%29.



In other words, 6%2Ax%5E2%2B25%2Ax%2B11=%283x%2B11%29%282x%2B1%29.



Note: you can check the answer by expanding %283x%2B11%29%282x%2B1%29 to get 6%2Ax%5E2%2B25%2Ax%2B11 or by graphing the original expression and the answer (the two graphs should be identical).