SOLUTION: Could you help me please?Tutor my division is: (3x^3+4x^2-4x-6)/(x-1)
would this be 16- 8? Does x=8? thank you
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-> SOLUTION: Could you help me please?Tutor my division is: (3x^3+4x^2-4x-6)/(x-1)
would this be 16- 8? Does x=8? thank you
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You can put this solution on YOUR website! Could you help me please?Tutor my division is: (3x^3+4x^2-4x-6)/(x-1)
would this be 16- 8? Does x=8? thank you
:
They aren't asking you what x equals. You are just dividing one expression by
another expression. The quotient will also be an expression
:
You can use ordinary long division, will use "......." to keep things lined up
Much the same as you do with numbers
:
........................3x^2 + 7x + 3
..........-------------------------
(x-1)|3x^3 + 4x^2 - 4x - 6
...........3x^3 - 3x^2; choose 1st term in the quotient: 3x^2 * x = 3x^3
...........------------
........................7x^2 - 4x
........................7x^2 - 7x; choose the 2nd term: 7x * x = 7x^2
........................----------
.....................................+3x - 6
.....................................+3x - 3; choose the 3rd term: 3* x = 3x
.....................................---------
............................................-3
:
The quotient: 3x^2 + 7x + 3; remainder:
:
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