SOLUTION: Find 'n' 1+3+...+2n-1=10(4n+50) Do I have to do something with (2n-1+2)(2n-1) I have no idea. Please help.

Algebra ->  Equations -> SOLUTION: Find 'n' 1+3+...+2n-1=10(4n+50) Do I have to do something with (2n-1+2)(2n-1) I have no idea. Please help.      Log On


   

Question 863270: Find 'n'
1+3+...+2n-1=10(4n+50)
Do I have to do something with (2n-1+2)(2n-1)
I have no idea. Please help.
Found 2 solutions by metodi022, lenny460:
Answer by metodi022(3) About Me  (Show Source):
Answer by lenny460(1073) About Me  (Show Source):
You can put this solution on YOUR website!
Please repost your question.