SOLUTION: (4a-2b^0c^1)^2 (-2a^3bc^-2)^3 ___________ ___________ _____ (-4a^2c^-4)^3 I don't know even where to begin with this fraction.

Algebra ->  Equations -> SOLUTION: (4a-2b^0c^1)^2 (-2a^3bc^-2)^3 ___________ ___________ _____ (-4a^2c^-4)^3 I don't know even where to begin with this fraction.       Log On


   

Question 861267: (4a-2b^0c^1)^2 (-2a^3bc^-2)^3
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(-4a^2c^-4)^3
I don't know even where to begin with this fraction.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
First simplify each term,
b%5E0=1
%284a%5E%28-2%29b%5E0c%5E1%29%5E2=16a%5E%28-4%29c%5E2
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%28-2a%5E3bc%5E%28-2%29%29%5E3=-8a%5E9b%5E3c%5E%28-6%29
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%28-4a%5E2c%5E%28-4%29%29%5E3=-64a%5E6c%5E%28-12%29
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