SOLUTION: 12(3x^2-2x+5)=7(5x^2-3x+10)

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Question 858563: 12(3x^2-2x+5)=7(5x^2-3x+10)
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
36x%5E2-24x%2B60=35x%5E2-21x%2B70
x%5E2-3x-10=0
%28x-5%29%28x%2B2%29=0
Two solutions:
x-5=0
x=5
and
x%2B2=0
x=-2