SOLUTION: Two sisters, Janet and Nora, each have a box holding 20 chocolates. Janet eats 5 and gives some away to her friends. Nora gives 1 away and eats three times as many as Janet has giv

Algebra ->  Equations -> SOLUTION: Two sisters, Janet and Nora, each have a box holding 20 chocolates. Janet eats 5 and gives some away to her friends. Nora gives 1 away and eats three times as many as Janet has giv      Log On


   



Question 856489: Two sisters, Janet and Nora, each have a box holding 20 chocolates. Janet eats 5 and gives some away to her friends. Nora gives 1 away and eats three times as many as Janet has given away. When they compare boxes, each sister still has the same number of chocolates left as the other. If Janet gave x chocolates away, form an equation in x and solve it. How many chocolates did Nora eat?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Janet starts with +20+, eats and gives away +5+%2B+x+,
so she has +20+-+%28+5+%2B+x+%29+ left
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Nora eats +3x+, gives +1+ away, so she has
+20+-+%28+1+%2B+3x+%29+ left
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They have the same number left, so
+20+-+%28+5+%2B+x+%29+=+20+-+%28+1+%2B+3x+%29+
+-5+-+x+=+-1+-+3x+
+5+%2B+x+=+1+%2B+3x+
+2x+=+4+
+x+=+2+
Nora ate +3x+=+6+ chocolates
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check:
Janet ate & gave away +5+%2B+x+=+7+
She had +20+-+7+=+13+ left
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Nora ate & gave away +1+%2B+3x+=+7+
She had +20+-+7+=+13+ left
OK