SOLUTION: Hi, I need help on getting this answer Solve for x and y by elimination or substitution <img src="http://formula.algebra.com/cgi-bin/plot-formula.mpl?expression=%0D%0A%28x-2%29%2

Algebra ->  Equations -> SOLUTION: Hi, I need help on getting this answer Solve for x and y by elimination or substitution <img src="http://formula.algebra.com/cgi-bin/plot-formula.mpl?expression=%0D%0A%28x-2%29%2      Log On


   



Question 856404: Hi, I need help on getting this answer
Solve for x and y by elimination or substitution


Found 2 solutions by mananth, KMST:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x and y by elimination or substitution
%28x-2%29%2F3+%2B+%28y%2B1%29%2F5+=2
multiply equation by 15
5(x-2)+3(y+1) = 30
5x-10+3y+3=30
5x+3y=37................................(1)
%28x%2B2%29%2F7+-+%28y%2B5%29%2F3+=-2
multiply equation by 21 (7*3)
3(x+2)-7(y+5)=-42
3x+6-7y-35=-42
3x-7y=-13..................................(2)
5 x + 3 y = 37 .............1
Total value
3 x -7 y = -13 .............2
Eliminate y
multiply (1)by 7
Multiply (2) by 3
35 x 21 y = 259
9 x -21 y = -39
Add the two equations
44 x = 220
/ 44
x = 5
plug value of x in (1)
5 x + 3 y = 37
25 + 3 y = 37
3 y = 37 -25
3 y = 12
y = 4
(5,4)


Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
There is more than one way to go about it, but I do not like to have to write all those denominators.
To start, I would eliminate denominators by multiplying times a convenient factor, and the I would simplify:

%28x-2%29%2F3%2B%28y%2B1%29%2F5=2-->15%28x-2%29%2F3%2B15%28y%2B1%29%2F5=2%2A15-->5%28x-2%29%2B3%28y%2B1%29=30-->5x-10%2B3y%2B3=30-->5x%2B3y=30%2B10-3-->5x%2B3y=37

%28x%2B2%29%2F7-%28y%2B5%29%2F3=-2-->21%28x%2B2%29%2F7-21%28y%2B5%29%2F3=-2%2A21-->3%28x%2B2%29-7%28y%2B5%29=-42-->3x%2B6-7y-35=-42-->3x-7y=-42-6%2B35-->3x-7y=-13

Then I would set to solve the system
system%285x%2B3y=37%2C3x-7y=-13%29 by elimination.
Multiplying the first equation times 3, and the second times -5,
and adding the resulting equations, I would get
15x + 9y = 111
-15x +35y = 65
-----------------
0x +44y = 176 --> 44y=176 --> y=176%2F44 --> highlight%28y=4%29
Then I would substitute 4 for y in 5x%2B3y=37 to get
5x%2B3%2A4=37-->5x%2B12=37-->5x=37-12-->5x=252-->x=25%2F5-->highlight%28x=5%29