SOLUTION: Hey,
Are you able to help me with this math question, I've tried but can't seem to figure the answer.
Any ideas?
Here is the picture of the question as I couldn't write it
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-> SOLUTION: Hey,
Are you able to help me with this math question, I've tried but can't seem to figure the answer.
Any ideas?
Here is the picture of the question as I couldn't write it
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Question 853989: Hey,
Are you able to help me with this math question, I've tried but can't seem to figure the answer.
Any ideas?
Here is the picture of the question as I couldn't write it out in the browser
http://gyazo.com/1070aa9922e91552e7fcf5a50b39faf7 Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! h = -4.9t^2 + 19.6t - 9.6
max height occurs on the axis of symmetry, the equation for that is: x = -b/2a
In this problem
x = t
a = -4.9
b = 19.6
:
t =
t = + 2 sec when max height occurs
:
Find max height, replace t with 2 and find h
h = -4.9(2^2) + 19.6(2) - 9.6
h = -19.6 + 39.2 - 9.6
h = 10 meters is max height
