SOLUTION: let g and h be two functions defined by: g(x)=(x-1)(x-6) h(x)=-9x+1 for any real number x. Find g/h(2) and then find all values that are NOT in the domain of g/h.

Algebra ->  Equations -> SOLUTION: let g and h be two functions defined by: g(x)=(x-1)(x-6) h(x)=-9x+1 for any real number x. Find g/h(2) and then find all values that are NOT in the domain of g/h.       Log On


   

Question 842649: let g and h be two functions defined by:
g(x)=(x-1)(x-6)
h(x)=-9x+1
for any real number x.
Find g/h(2) and then find all values that are NOT in the domain of g/h. If there is more than one value, separate them with commas.
so I have g/h(2):
(x-1)(x-6)/-9x+1(2)
I don't know how to find the values that are NOT in the domain of g/h.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
h(2)=-9*2+1
h(2)=-17

g%2Fh%282%29=%28x-1%29%28x-6%29%2Fh%282%29=-%28x-1%29%28x-6%29%2F17.
The domain for this is all real numbers.

The domain for g%28x%29%2Fh%28x%29?
%28x-1%29%28x-6%29%2F%28-9x%2B1%29.
Values of x NOT in the domain of g/h is only one value.
The ratio g/h cannot accept -9x%2B1=0
-9x=-1
9x=1
highlight%28x=1%2F9%29-------This is the value of x NOT in the domain of g%28x%29%2F%28h%28x%29%29.