SOLUTION: When the piñata burst at Amy’s party, she was able to grab 48 pieces of candy, which was 3/7 of the candy that fell out of the piñata. She was thrilled until she noticed that som

Algebra ->  Equations -> SOLUTION: When the piñata burst at Amy’s party, she was able to grab 48 pieces of candy, which was 3/7 of the candy that fell out of the piñata. She was thrilled until she noticed that som      Log On


   

Question 839004: When the piñata burst at Amy’s party, she was able to grab 48 pieces of candy, which was
3/7 of the candy that fell out of the piñata. She was thrilled until she noticed that some of
her friends did not get any candy. If everyone put their candy back into one pile, and the
candy was then distributed evenly amongst Amy and her six friends, how many pieces of
candy did each of Amy’s friends receive?

Answer by PRMath(133) About Me  (Show Source):
You can put this solution on YOUR website!
When you want to know the percent or fraction of a number you always multiply.
SO! When Amy grabbed 3/7 of the candy, she had 48 pieces. This means that 3/7 of a certain number is 48. If we say "x" is the unknown, then we know this applies:
3/7(x) = 48 Now we solve. Multiply both sides by 7 and we get:
3x = 336 Divide both sides by 3 and we get:
x = 112.
THEREFORE, originally there were 112 pieces of candy in the pinata. Now all those pieces of candy must be distributed between Amy and her six friends. There are 7 people in all, so we divide 112 by 7 and we get:
16