SOLUTION: Find the x-intercepts. y = x^2 – 4x + 4 I came across this and I was wondering how these are done? Can someone show me please?

Algebra ->  Equations -> SOLUTION: Find the x-intercepts. y = x^2 – 4x + 4 I came across this and I was wondering how these are done? Can someone show me please?      Log On


   



Question 83688: Find the x-intercepts.
y = x^2 – 4x + 4
I came across this and I was wondering how these are done? Can someone show me please?

Found 2 solutions by josmiceli, stanbon:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The x-intercepts are where y=0
x%5E2+-+4x+%2B+4+=+0
%28x-2%29%5E2+=+0
When x=2, y=0, so the x-intercept is x=2

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find the x-intercepts.
y = x^2 – 4x + 4
To find the x-intercept let y = 0:
x^2-4x+4=0
(x-2)^2=0
x-2=0
x=2 with multiplicity two
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The graph will touch the x-axis at x=2 but will not pass thru the x-axis.
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graph%28400%2C300%2C-10%2C10%2C-10%2C10%2Cx%5E2-4x%2B4%29
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Cheers,
Stan H.