SOLUTION: Hi Please help me find this (the answers for both X& Y should be integer), the answers are 9& 3 but I don't know the procedure to find them. I really need this to learn so plea

Algebra ->  Equations -> SOLUTION: Hi Please help me find this (the answers for both X& Y should be integer), the answers are 9& 3 but I don't know the procedure to find them. I really need this to learn so plea      Log On


   



Question 825789: Hi
Please help me find this (the answers for both X& Y should be integer), the answers are 9& 3 but I don't know the procedure to find them.
I really need this to learn so please give me the algorithm to solve such problems except trial and error if there is any or in case just by trial and error how to find the best guess for start point near final answers.
Thanks
X+Y+6XY=174 (X=9 Y=3)

Answer by math-vortex(648) About Me  (Show Source):
You can put this solution on YOUR website!
Hi, there--

THE PROBLEM:
Solve for x and y.
X + Y + 6XY = 174

A SOLUTION:
First of all, you are correct that one solution to this equation is (X,Y)=(3,9). There infinitely 
many pairs of X and Y that make this equation true.

One strategy to find solutions would be to rewrite the equation in "Y=" form so you have an 
explicit expression for Y in terms of X.

Isolate the terms that have a Y in them on the left side of the equation by subtracting X from 
both sides.

Y%2B6XY=174-X

Factor Y out of each term on the left side.
%28Y%29%281%2B6X%29+=174-X

Divide both sides of the equation by (1-6X).

Y=%28174-X%29%2F%281%2B6X%29

Once you have the equation in this "Y=" form, you can: 
1. use a graphing calculator to investigate.
2. find any X-intecept by setting the numerator equal to zero.
3. find any y-intercept by setting X=0.

Here is a link to a graph of your equation. Any point on the curve is a solution to the equation.
(You will need to copy and paste it into your browser.

http://graphsketch.com/?eqn1_color=1&eqn1_eqn=(174-X)%2F(1%2B6X)&eqn2_color=2&eqn2_eqn=&eqn3_color=3&eqn3_eqn=&eqn4_color=4&eqn4_eqn=&eqn5_color=5&eqn5_eqn=&eqn6_color=6&eqn6_eqn=&x_min=-17&x_max=17&y_min=-10.5&y_max=10.5&x_tick=1&y_tick=1&x_label_freq=5&y_label_freq=5&do_grid=0&do_grid=1&bold_labeled_lines=0&bold_labeled_lines=1&line_width=4&image_w=850&image_h=525


Hope this helps! Feel free to email if you have any questions.

Mrs. Figgy
math.in.the.vortex@gmail.com