SOLUTION: solve for k 4k+3/6+4k-8/9=5k-4/3-k-3/2 a. k=-4 b. k=-10 c. k=44 d. k=58

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Question 823637: solve for k 4k+3/6+4k-8/9=5k-4/3-k-3/2
a. k=-4
b. k=-10
c. k=44
d. k=58
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
%284k%2B3%29%2F6%2B%284k-8%29%2F9=%285k-4%29%2F3-%28k-3%29%2F2 Start with the given equation.


%281%2F6%29%284k%2B3%29%2B%281%2F9%29%284k-8%29=%281%2F3%29%285k-4%29-%281%2F2%29%28k-3%29 Rearrange terms


%282%2F3%29k%2B1%2F2%2B%284%2F9%29k-8%2F9=%285%2F3%29k-4%2F3-%281%2F2%29k%2B3%2F2 Distribute.


Multiply both sides by the LCD 18 to clear any fractions.


12k%2B9%2B8k-16=30k-24-9k%2B27 Distribute and multiply.


20k-7=30k-24-9k%2B27 Combine like terms on the left side.


20k-7=21k%2B3 Combine like terms on the right side.


20k=21k%2B3%2B7 Add 7 to both sides.


20k-21k=3%2B7 Subtract 21k from both sides.


-k=3%2B7 Combine like terms on the left side.


-k=10 Combine like terms on the right side.


k=%2810%29%2F%28-1%29 Divide both sides by -1 to isolate k.


k=-10 Reduce.


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Answer:

So the solution is k=-10