Question 809443: what is the equation y=-.5x-4 in slope-intercept form for a line perpendicular to the graph of the equation that passes through the x-intercept of that line?
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! L1:
y = -.5x - 4
same as:
y = (-1/2)x - 4
slope (m) = (-1/2)
x-intercept (a) = 4(-2) = (-8, 0)
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L2:
perpendicular lines have negative reciprocal slopes:
mp = 2
use the point-slope form with x-intercept of L1:
y - y1 = mp(x - x1)
y = 2(x + 8)
Answer:
eqn. of perp. line in slope-intercept form:
y = 2x + 16
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