SOLUTION: I am sorry guys some of the question was left out. Which of the pairs are solutions for the equation x-y=4 (a) (0,4), (-4,0), and (-3-7) (b) (-4,0), and (-3,-7) (c)

Algebra ->  Equations -> SOLUTION: I am sorry guys some of the question was left out. Which of the pairs are solutions for the equation x-y=4 (a) (0,4), (-4,0), and (-3-7) (b) (-4,0), and (-3,-7) (c)       Log On


   

Question 80718: I am sorry guys some of the question was left out.

Which of the pairs are solutions for the equation x-y=4
(a) (0,4), (-4,0), and (-3-7)
(b) (-4,0), and (-3,-7)
(c) (0, -4) and (-3-7)
(d) (3, 1) and (-4, 0)
with instructions of what was done to get the answer, thank you I am sorry for the first one
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
To see which solutions make x-y=4 true, simply plug in the possible solutions into x and y:
Lets plug in (0,4)

0-4=4
-4=4 not true. So this eliminates answer a)

Now lets try b)
Plug in (-4,0)
-4-0=4
-4=4 not true. So this eliminates answer b)

Now lets try c)
Plug in (0,-4)

0-%28-4%29=4
0%2B4=4
4=4 true
Now lets plug in (-3,-7)
-3-%28-7%29=4
-3%2B7=4
4=4 true. So this means c) is an answer.

For the sake of the problem, lets try d) as well
Plug in (3,1)

3-1=4

2=4 not true. So this eliminates answer d)


So the only answer that satisfies x-y=4 is answer c)