SOLUTION: Please help me solve this equation: {{{2^x=0.125}}} .

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Question 803280: Please help me solve this equation: 2%5Ex=0.125 .
Found 2 solutions by lwsshak3, DrBeeee:
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
solve this equation: 2%5Ex=0.125
***
use logs:
xlog(2)=log(0.125)
x=log(0.125)/log(2)
x=-3

Answer by DrBeeee(684) About Me  (Show Source):
You can put this solution on YOUR website!
Given:
(1) 2%5Ex+=+0.125
Take the ln of each side, obeying the rule for ln of a power, ln(a^b) = b*ln(a), to get
(2) x%2Aln%282%29+=+ln%280.125%29 or
(3) x = ln(0.125)/ln(2)
Use your scientific calculator to get
(4) x = -3
Check your answer with (1).
Is (2^(-3) = 0.125)?
Is (0.125 = 0.125)? Yes
Answer: x = -3
You may also recognize that 0.125 = 1/8 or 1/(2^3) or 2^(-3), so you have
(5) 2^x = 2^(-3) from which you see that
(6) x = -3
If you don't see it, take the ln of each side of (5) to get
(7) x*ln(2) = (-3)*ln(2) or
(8) x = (-3)*ln(2)/ln(2) or
(9) x = -3