SOLUTION: I have slept on a waterbed since the 70's. Last year I had to replace the mattress. The waterbed mattress measures 80 inches by 84 inches by 10 inches tall. I filled the matress to

Algebra ->  Equations -> SOLUTION: I have slept on a waterbed since the 70's. Last year I had to replace the mattress. The waterbed mattress measures 80 inches by 84 inches by 10 inches tall. I filled the matress to      Log On


   



Question 783400: I have slept on a waterbed since the 70's. Last year I had to replace the mattress. The waterbed mattress measures 80 inches by 84 inches by 10 inches tall. I filled the matress to capacity with water that I thought was about 92 degrees, but after the bed was filled I found out that the actual temperature was only 74 degrees. It took 3 days for the waterbed heater to warm it up to 92 degrees. I had to sleep on the couch for 3 nights.
One thing that I could have done was drain out part of the water and replace it with 140 degree water. If I had done this, how many gallons of the "colder" water would I have had to drain out of the bed and replace with the 140 degree water, so that the temperature of the bed would have been 92 degrees?
Note: 231 Cubic Inches = 1 Gallon
Soooooo confused on this question. Any help understanding would be great, thank you!

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = amt of 74 degree water to be drain & amt of 140 degree water to be added
Find the no. of gallons total
%2880%2A84%2A10%29%2F231 ~ 290 gallons
:
74(290-x) + 140x = 92(290)
21460 - 74x + 140x = 26680
-74x + 140x = 26680 - 21460
66x = 5220
x = 5220/66
x ~ 79 gallons
:
Drain 79 gallons of the 74 degree water out
Add 79 gallons of the 140 degree water
Should result in 92 degree water