The first term has one factor of 7 and 3 factors of a. The second term has two factors of 2, one factor of 7, and one factor of a. One factor of 7 and one factor of a are common, so:
is the complete factorization over the real numbers.
is the complete factorization over the complex numbers.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
You can put this solution on YOUR website! Can you factor 7a^3 + 28a?
----
Common factor:: 7a
----
= 7a(a^2+4)
----
If you allowed to factor over the complex numbers you get:
----
= 7a(a+2i)(a-2i)
================
Cheers,
Stan H.
================