SOLUTION: Hi there, I was wondering if someone can help me solve this rectangle problem? It says: The length of a rectangle decreased by 6cm is equal to the width. If the perimeter is

Algebra ->  Equations -> SOLUTION: Hi there, I was wondering if someone can help me solve this rectangle problem? It says: The length of a rectangle decreased by 6cm is equal to the width. If the perimeter is      Log On


   

Question 77607: Hi there, I was wondering if someone can help me solve this rectangle problem?
It says:
The length of a rectangle decreased by 6cm is equal to the width. If the perimeter is 68 cm, find its dimensions.
It would be greatly appreciated!!!!
Thank you.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
If we let L=length, w=width we get

L-6=w and the perimeter equals
P=2L%2B2w

68=2L%2B2%28L-6%29 Plug in L-6 into w and let P=68

68=2L%2B2L-12 Distribute

68=4L-12 Combine like terms


80=4L Add 12 to both sides

80%2F4=L Divide both sides by 4

L=20 So this is the length
Use this to find the width:
20-6=w
w=14
So the dimensions are width=14, length=20
Check:
68=2%2820%29%2B2%2814%29 plug in L=20, w=14, P=68
68=40%2B28
68=68 works