You can put this solution on YOUR website! Q:
what is the length of the segment of line 3x+ 4y = 12 that is in the first quadrant?
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A:
First we get the x-intercept:
Let y = 0 and solve for x
3x + 4(0) = 12
3x = 12
x = 4
The x-intercept is (4,0)
Next, we get the y-intercept:
Let x = 0 and solve for y
3(0) + 4y = 12
4y = 12
y = 3
The y-intercept is (0,3).
Finally, we get the distance between the x and y-intercept using the
distance formula.
d = = =
Answer:
