SOLUTION: For a game, I need to solve the following question: 4(x+3)+2-8(x+4)=2x-3-4(x+2)-60/x This is what I have so far: 4X+12+2-8X-32=2X-3-4X-8-(60/x) 4X-8X-2X+4X+(60/X)=-12-2+32-3-

Algebra ->  Equations -> SOLUTION: For a game, I need to solve the following question: 4(x+3)+2-8(x+4)=2x-3-4(x+2)-60/x This is what I have so far: 4X+12+2-8X-32=2X-3-4X-8-(60/x) 4X-8X-2X+4X+(60/X)=-12-2+32-3-      Log On


   

Question 770341: For a game, I need to solve the following question:
4(x+3)+2-8(x+4)=2x-3-4(x+2)-60/x
This is what I have so far:
4X+12+2-8X-32=2X-3-4X-8-(60/x)
4X-8X-2X+4X+(60/X)=-12-2+32-3-8
-2X+(60/X) = 7
Now I'm stuck. Please help me out how to solve this. Thank you!

Answer by ramkikk66(644) About Me  (Show Source):
You can put this solution on YOUR website!
You've proceeded correctly so far!
Continue from the last equation
-2X+(60/X) = 7
Multiplying by x
-2*x^2 + 60 = 7*x
2%2Ax%5E2+%2B+7%2Ax+-+60+=+0
This is a standard quadratic equation which can be solved by factorizing
2%2Ax%5E2+-+8%2Ax+%2B+15%2Ax+-+60+=+0
%282%2Ax+%2B+15%29%2A%28x+-+4%29+=+0
So the 2 roots are
2*x + 15 = 0, or x = -15/2
x - 4 = 0, or x = 4
Hope you got it :)