You can put this solution on YOUR website! Given:
(1) 2/(3-t) + 1/(3+t) + 1/(9-t^2) = 0
Note that the denominator of the third term factors into
(2) 9-t^2 = (3+t)*(3-t)
If we multiply both sides of (1) by (2) we get
(3) 2*(3+t) + (3-t) +1 = 0 or
(4) 6+2t +3-t +1 = 0 or
(5) t + 10 = 0 or
(6) t = -10
Is (2/13 + 1/(-7) - 1/91 = 0)?
Is (14/91 - 13/91 - 1/91 = 0)?
Is (1/91 - 1/91 = 0)?
Is (0 = 0)? Yes
Answer: t = -10