SOLUTION: find the standard form of an equation for each graph described slope = 3/4,y-intercept = -3 my try: m=3/4 (-3,0) y=3/4x + b 0 = 3/4 x -3/1 + b 0 = -9/4 + b 9/4 =

Algebra ->  Equations -> SOLUTION: find the standard form of an equation for each graph described slope = 3/4,y-intercept = -3 my try: m=3/4 (-3,0) y=3/4x + b 0 = 3/4 x -3/1 + b 0 = -9/4 + b 9/4 =       Log On


   

Question 76627: find the standard form of an equation for each graph described
slope = 3/4,y-intercept = -3
my try: m=3/4 (-3,0)
y=3/4x + b
0 = 3/4 x -3/1 + b
0 = -9/4 + b
9/4 = b ????
Answer by wodkit02(9) About Me  (Show Source):
You can put this solution on YOUR website!
Since we are given the slope and the y-intercept, we have the equation in slope-intercept form: y = mx + b
m = 3/4; b (or the y-intercept) = -3
y = 3%2F4x - 3

Standard form looks like this : Ax + By = C, where A, B, and C are all integer constants. Let's get y and x on the same side.
y = 3%2F4x - 3
-3%2F4x + y = -3
Now we need to multiply everything by 4 so the fraction can become an integer:
4 * -3%2F4x + 4 * y = 4 * -3
-3x + 4y = -12
Since all the constants are integer values, we are done.