SOLUTION: Okay, so the problem is (x+2)^2=-7
I simplified it to (x+2)(x+2)=-7. And then I did, x^2+4x+4=-7. I added the negative 7 to the 4 making the problem x^2+4x+11=0 and then that's wh
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-> SOLUTION: Okay, so the problem is (x+2)^2=-7
I simplified it to (x+2)(x+2)=-7. And then I did, x^2+4x+4=-7. I added the negative 7 to the 4 making the problem x^2+4x+11=0 and then that's wh
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Question 763687: Okay, so the problem is (x+2)^2=-7
I simplified it to (x+2)(x+2)=-7. And then I did, x^2+4x+4=-7. I added the negative 7 to the 4 making the problem x^2+4x+11=0 and then that's when I tried to use the quadratic formula but it comes out as -4 +over- radical -28 all over 2. Help me please!!!!!!!! Answer by josgarithmetic(39616) (Show Source):
You can put this solution on YOUR website! Your steps are in the wrong direction. The given equation is in a form easy to solve for x. Trying to factor, or trying to put into general form is counter productive. Just solve for x without any tricks. Do you see, just by looking at the equation, the solution will contain imaginary numbers?
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