SOLUTION: Completing the square x^2-2x-8=0 Im stuck on this thanks!

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Question 750565: Completing the square x^2-2x-8=0
Im stuck on this thanks!
Found 3 solutions by FrankM, MathLover1, lwsshak3:
Answer by FrankM(1040) About Me  (Show Source):
You can put this solution on YOUR website!
x^2-2x-8=0
x^2-2x+1-1-8=0
x^2-2x+1=9
(x-1)^2=9
x-1 = -3 x-1 = 3
x=-2 x=4



Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

+x%5E2-2x-8=0....write -2x as 2x-4x
+x%5E2%2B2x-4x-8=0....group
+%28x%5E2%2B2x%29-%284x%2B8%29=0
+x%28x%2B2%29-4%28x%2B2%29=0
+%28x-4%29%28x%2B2%29=0

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Completing the square x^2-2x-8=0
x^2-2x-8=0
(x^2-2x+1)-1-8=0
(x-1)^2=9
x-1=±√9
x=1±3