Question 75022: Find
(c - 5)(c - 7)
(3y - 4)(2y^2 + y - 1)
Help.
Answer by cathieb1225(41)   (Show Source):
You can put this solution on YOUR website! (c - 5)(c - 7)
Multiply c to both terms in the second parentheses,then multiply -5 to both terms in the second parentheses
c^2-7c-5c+35
Combine like terms,-7c and -5c
c^2-12c+35
(3y - 4)(2y^2 + y - 1)
Do the same thing with this problem, distributing both the first and second term in the first parentheses with the ones in the second parentheses
6y^3+3y^2-3y-8y^2-4y+4
Combine like terms
6y^3-5y^2-7y+4
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