SOLUTION: What is the equation of a horizontal line that passes through the point at (-2,-3)? I have been working on this problem and I still do not understand it. May some one please hel

Algebra ->  Equations -> SOLUTION: What is the equation of a horizontal line that passes through the point at (-2,-3)? I have been working on this problem and I still do not understand it. May some one please hel      Log On


   

Question 74674: What is the equation of a horizontal line that passes through the point at (-2,-3)?
I have been working on this problem and I still do not understand it. May some one please help me? Thank you
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
A horizontal line will have the slope of 0. This is because the y value does not change but the x value changes. For instance, in the slope formula
m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 a horizontal line will have identical y values while the x changes. For instance, if we pick a horizontal line that goes through (0,2) and (2,2) we get:
m=%282-2%29%2F%282-0%29=0%2F2=0
So any horizontal line will have a slope of zero. Now plug in m=0 and the point (-2,-3) into the point slope equation
y-y%5B1%5D=m%28x-x%5B1%5D%29
y-%28-3%29=0%28x-%28-2%29%29Plug in m=0 and (x%5B1%5D,y%5B1%5D)=(-2,-3)
y%2B3=0x%2B2%280%29Distribute the 0 to each term
y=0-3Subtract 3 from both sides
So the equation is
+y=-3
If we graphed the equation, we would get:
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+-3%29+Graph of y=-3(dark red line)