SOLUTION: 4x2y/2xy3= The 2 after the x is squared. The 3 after the y is cubed. I tried listening in class but it's not clicking. I need some big help! Thankyou.

Algebra ->  Equations -> SOLUTION: 4x2y/2xy3= The 2 after the x is squared. The 3 after the y is cubed. I tried listening in class but it's not clicking. I need some big help! Thankyou.       Log On


   

Question 74361This question is from textbook Addison-Wesley Algebra
: 4x2y/2xy3=
The 2 after the x is squared. The 3 after the y is cubed. I tried listening in class but it's not clicking. I need some big help! Thankyou. This question is from textbook Addison-Wesley Algebra

Found 2 solutions by checkley75, jim_thompson5910:
Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
IT'S BEST TO BREAK THESE DOWN TO THE COMMON ITEMS AS FRACTIONS & REDUCE EACH INDIVIDUALLY.
4X^2Y/2XY^3
4/2=2
X^2/X=X
Y/Y^3=1/Y^2 NOW COMBINE THE INDIVIDUAL ELEMENTS THUS:
2X/Y^2

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
4x%5E2y%2F2xy%5E3
4x%5E2y%5E1%2F2x%5E1y%5E3When dividing like bases with exponents we subtract the exponents. If I have x%5E2%2Fx it translates to x%2Across%28x%29%2Fcross%28x%29=x or x%5E2%2Fx=x%5E2%2Fx%5E1=x%5E%282-1%29=x%5E1=x. So we're going to apply the same idea for this problem.
4x%5E%282-1%29y%5E%281-3%29%2F2
4x%5E1y%5E%28-2%29%2F2Simplify 4/2 to 2
2x%5E1y%5E%28-2%29When we have negative exponents, we invert the base (ie x%5E%28-2%29=1%2Fx%5E2 because if we have . So x%5E%28-a%29=1%2Fx%5Ea
%282x%5E1%29%2F%28y%5E%282%29%29
2x%2Fy%5E2Here's the simplified form.