SOLUTION: How many liters of a 10% saline solution must be mixed with 20 liters of a 15% saline solution to make a 12% saline solution?

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Question 737783: How many liters of a 10% saline solution must be mixed with 20 liters of a 15% saline solution to make a 12% saline solution?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = liters of 10% solution needed
+.1x+ = liters of salt in 10% solution
+.15%2A20+=+3+ liters of salt in 15% solution
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+%28+.1x+%2B+3+%29+%2F+%28+x+%2B+20+%29+=+.12+
+.1x+%2B+3+=+.12%2A%28+x+%2B+20+%29+
+.1x+%2B+3+=+.12x+%2B+2.4+
+.02x+=+.6+
+x+=+30+
30 liters of 10% solution are needed
check:
+%28+.1x+%2B+3+%29+%2F+%28+x+%2B+20+%29+=+.12+
+%28+.1%2A30+%2B+3+%29+%2F+%28+30+%2B+20+%29+=+.12+
+%28+3%2B+3+%29+%2F+50+=+.12+
+6+=+.12%2A50+
+6+=+6+
OK