SOLUTION: A mechanic has found that a car with a 16-quart radiator has 40% antifreeze mixture in the radiator. He has a 80% antifreeze solution. How much of the 40% solution would he have to
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Question 733612: A mechanic has found that a car with a 16-quart radiator has 40% antifreeze mixture in the radiator. He has a 80% antifreeze solution. How much of the 40% solution would he have to replace with the 80% solution to get the radiator up to 55% antifreeze solution? (You must set up an equation and solve to receive credit) Answer by KMST(5328) (Show Source):
You can put this solution on YOUR website! The radiator contains 16 quarts of solution that is too weak.
If the mechanic removes quarts of the 40% solution in the radiator, the radiator will have quarts of solution, containing quarts of antifreeze.
After that, the mechanic adds quarts of 80% antifreeze solution, containing quarts of antifreeze.
At the end, the radiator will again contain 16 quarts of solution: , but the amount of antifreeze in the radiator will be
For the solution to be 55% antifreeze, the amount of antifreeze in the radiator should be quarts or quarts
The equation we should use to calculate the value needed is or --> --> --> --> --> -->
The mechanic should remove 6 quarts of solution from the radiator and replace them with 6 quarts of 80% antifreeze solution.
