SOLUTION: x sqrd/49-y sqrd/81=1, what are the slopes of the asymptotes?

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Question 730543: x sqrd/49-y sqrd/81=1, what are the slopes of the asymptotes?
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
x sqrd/49-y sqrd/81=1, what are the slopes of the asymptotes?
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x^2/49-y^2/81=1
This is an equation of a hyperbola with horizontal transverse axis.
Its standard form of equation: %28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1
slopes of hyperbolas with horizontal transverse axis=±b/a
For given equation:
a^2=49
a=7
b^2=81
b=9
slopes=±b/a=±9/7
..
Notes:
Slopes of hyperbolas with vertical transverse axis=±a/b
Equations of asymptotes are straight lines that go thru the center of the hyperbola