SOLUTION: If one number exceeds another number by 3 and the square of the larger exceeds the square of the smaller by 99, what are the numbers?

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Question 726429: If one number exceeds another number by 3 and the square of the larger exceeds the square of the smaller by 99, what are the numbers?
Answer by fcabanski(1391) About Me  (Show Source):
You can put this solution on YOUR website!
Call the numbers x and y.


Condition 1: x=y+3. Condition 2: x%5E2+=+y%5E2+%2B+99


Substitute x=y+3 into the second equation: %28y%2B3%29%5E2+=+y%5E2+%2B+99


y%5E2+%2B6y+%2B+9+=+y%5E2+%2B99 ---> (subtract y squared from both sides and subtract 9 from both sides): 6y = 90 ---> y = 15.


x = 15+ 3 = 18

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