SOLUTION: Please help me solve this equation... {{{(1-3x)/4=(x+6)/3+1/2}}} This is on the chapter review page 190 problem #12

Algebra ->  Equations -> SOLUTION: Please help me solve this equation... {{{(1-3x)/4=(x+6)/3+1/2}}} This is on the chapter review page 190 problem #12      Log On


   

Question 72120This question is from textbook College Algebra Enhanced
: Please help me solve this equation...
%281-3x%29%2F4=%28x%2B6%29%2F3%2B1%2F2
This is on the chapter review page 190 problem #12 This question is from textbook College Algebra Enhanced

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Please help me solve this equation...
%281-3x%29%2F4=%28x%2B6%29%2F3%2B1%2F2
:
Mult by a common denominator to get rid of the denominators, 12 is a good one
%2812%29%281-3x%29%2F4=%2812%29%28x%2B6%29%2F3%2B%2812%291%2F2
:
All denominators cancel, leaving:
(3)(1-3x) = (4)(x+6) +(6)1
:
Multiply what's inside the brackets:
3 - 9x = 4x + 24 + 6
3 - 9x = 4x + 30
:
-9x - 4x = 30 - 3
:
-13x = 27
:
x = 27/-13
x = - 27/13, a rather annoying solution, but I checked it by substitution.