SOLUTION: ((x^2)y)+4=(x(y^2))-2, x=? and y=? I do not know where to start with this type of equation.

Algebra ->  Equations -> SOLUTION: ((x^2)y)+4=(x(y^2))-2, x=? and y=? I do not know where to start with this type of equation.      Log On


   

Question 720398: ((x^2)y)+4=(x(y^2))-2, x=? and y=?
I do not know where to start with this type of equation.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
((x^2)y)+4=(x(y^2))-2, x=? and y=?
I do not know where to start with this type of equation.
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You have parentheses that don't contribute anything.
x^2y + 4 = xy^2 - 2, x=? and y=?
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It's 1 equation with 2 variables.
What is it you want to do?
There's no unique solution of x & y.
You can pick any value for x and find y, or v.v.