SOLUTION: (2n-1)v^2-2nv+1=0 Please solve for v in equation. Here is my attempt (2n-1)v^2-2nv=-1 V[(2n-1)v-2n]=-1 V=-1÷(2nv-v-2n) I got stuck here.

Algebra ->  Equations -> SOLUTION: (2n-1)v^2-2nv+1=0 Please solve for v in equation. Here is my attempt (2n-1)v^2-2nv=-1 V[(2n-1)v-2n]=-1 V=-1÷(2nv-v-2n) I got stuck here.       Log On


   

Question 715439: (2n-1)v^2-2nv+1=0
Please solve for v in equation. Here is my attempt
(2n-1)v^2-2nv=-1
V[(2n-1)v-2n]=-1
V=-1÷(2nv-v-2n)
I got stuck here.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
%282n-1%29v%5E2-2nv%2B1=0
Recognize that this is in general form for quadratic equation in variable, v. You CAN use the general solution.

v=%282n-sqrt%284n%5E2-4%2A%282n-1%29%29%29%2F%282%282n-1%29%29, or v=%282n%2Bsqrt%284n%5E2-4%2A%282n-1%29%29%29%2F%282%282n-1%29%29 and continue to simplify from that.