SOLUTION: Hi,
I keep trying to figure out where I am going wrong in this equation but I cannot. The equation is...
a=b
a^2=ab
a^2-b^2=ab-b^2
(a+b)(a-b)=b(a-b)
a+b=b
a+a=a
2a=a
2=1
Algebra ->
Equations
-> SOLUTION: Hi,
I keep trying to figure out where I am going wrong in this equation but I cannot. The equation is...
a=b
a^2=ab
a^2-b^2=ab-b^2
(a+b)(a-b)=b(a-b)
a+b=b
a+a=a
2a=a
2=1
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Question 710207: Hi,
I keep trying to figure out where I am going wrong in this equation but I cannot. The equation is...
a=b
a^2=ab
a^2-b^2=ab-b^2
(a+b)(a-b)=b(a-b)
a+b=b
a+a=a
2a=a
2=1 Answer by Edwin McCravy(20055) (Show Source):
a=b
a^2=ab
a^2-b^2=ab-b^2
(a+b)(a-b)=b(a-b)
a+b=b <-- this step is wrong because you can only divide both
sides by a number other than zero, however the first
step is a=b which means that a-b = 0, so this step
is incorrect because it divides the preceding step
through by zero.
Edwin