You can put this solution on YOUR website!
.
Multiply out 2 times (p - 3) by multiplying 2 times each of the terms in the parentheses.
When you do this multiplication the result is 2p -6. Substitute this into the equation
in place of 2(p-3) to get:
.
.
Note on the left side that the -6 and the +6 cancel each other out so that the left side
reduces to just 2p. The equation is now:
.
.
The goal is to get all the terms that contain p on the left side. So what we need to
do is subtract 4p from the left side. But if we do that, we have to subtract 4p from the
left side also. [Whatever we do to one side of the equation, we have to do it to the
other side too.] By subtracting 4p from both sides we reduce the equation to:
.
.
Now we have to get rid of the -2 that multiplies p. We do this by dividing both sides of
the equation by -2. On the left side the -2 divides into the -2 multiplier of p to become
just 1. And 1p is written as just p. On the right side when the -10 is divided by -2,
the result is +5. Therefore, the answer is:
.
.
You can check this answer out by returning to the original equation and replacing p
by 5. Then work out both sides of the equation and see if the left side equals the right
side. If it does then the solution of p=5 works to keep the equation in balance.
So first replace p by 5 to get:
.
.
The 5-3 in parentheses equals 2 and when it is multiplied by the 2 in front of the parens
the result is 4. So the left side equals 4 + 6. The 5*4 in the parentheses on the right
side becomes 20. So the right side equals 20 -10. In equation form this is:
.
.
Obviously the left side is 10 and so is the right side. Therefore p = 5 is a solution to
the original equation.
.
Hope this helps you to understand the problem and how you use algebraic steps to work the
problem out to a solution.
(